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![[YCH] Amelia's latest catch](http://t.furaffinity.net/17601867@150-1441477004.jpg "[YCH] Amelia's latest catch")
Just me showin off my big TONGUE!
Blargh!
Character and art by me.
Blargh!
Character and art by me.
Category Artwork (Digital) / Vore
Species Alien (Other)
Size 1009 x 925px
File Size 288.4 kB
Listed in Folders
That killed me, really, like i imagine the scene
Doctor : So, you are sick, as you're saying?
Scourge : *nod*
Doctor : Well, show me you tounge, mister Scourge
Scourge : *Does as the doctor asked*
Doctor : That a big one, unlike my other patients
Scourge : *Eats the doctor as soon as he touches the sticky tounge, and feels better*
>w< I can only imagine that
Doctor : So, you are sick, as you're saying?
Scourge : *nod*
Doctor : Well, show me you tounge, mister Scourge
Scourge : *Does as the doctor asked*
Doctor : That a big one, unlike my other patients
Scourge : *Eats the doctor as soon as he touches the sticky tounge, and feels better*
>w< I can only imagine that
Hmmmm... Ok. ^w^
I'll give it a shot, but my calculating abilities might be a bit rusty.
Let's asume Scorge is looking at an angle of aprox. 45º (or ∏/4 rad). By extrapolating the visual data from the picture, we can see that Scorge is about 357 pixels tall (small/reduced version of the picture), which is equivalent to 9 ft, for scaling purposes. owo
To get the dimensions of the tongue, we can see that it is contained within a box of 206x186 pixels (from now on A). This makes the tongue be at a descending angle of approx. 42.07927848.
We can try to modelize this problem as a 3D affine geometry problem. We'll just need to use linear algebra to solve the problem. ^w^
Also, let's assume Scorge's tongue center is the origin, shall we? Makes it more simple to calculate by symetry (and it's probably the main focus point by now :P). We can calculate the plane that contains the projection of the line that goes across the tongue over the {X=0} plane (aka, the picture) and contains the OX axis, which we'll call p1. It's pretty simple to calculate, someone in high school should be able to do it. It's basically calculating the equations of a line in the real plane, then assume it's a projection in 3D in the {X=0} plane. The inclination is -186/206, so it's basically easy to see that the equation in R^2 is {103y+93x=0}. If we translate that to our problem, we get that p1 is basically {103z + 93y = 0}. Since we assumed Scorge was looking at an angle of 45º (and our point of view is basically aiming straight at Scorge's mouth), we will just intersect the plane we calculated before with a new vertical one that contains the further left edge of the box A and has a 45º angle towards the viewer compared to the perpendicular plane from the picture. We'll call this one p2. That one's also easy to calculate, it turns out to be p2={y=x-103}. The intersection of both results in the line: {103z+93y=0 ; y=x-103}
Let's limit the line to what we're mostly interested, shall we? The tip of the tongue and the back of it that is still visible. For simplicity's sake, we'll consider the top left corner and the bottom right corner of A as the limits. We just need to find what points do those represent in the line and calculate the distance between them. If z=93, then y=-103 and x=0. If z=-93, then y=103 and x=206.
With that, all we need to do is simply calculating the distance between the dots (0,-103,93) and (206,103,-93).
We just need to use the euclidean measure to get there. Square root of the norm of the vector that unites the dots. The result is aproximately 345.6414327 px.
With that, and knowing that Scorge in the picture is 357 px tall, which is equivalent to 9 ft, we can convert the px unit we've been using into ft. The result is 8.713649564 ft or, in other words, approx. 8 ft and 8.5 inches long.
So... There you go. Scorge's tongue is approximately 8 ft and 8.5 inches long (or at least the part seen in the picture).
Keep in mind that:
a) My calculating abilities are a bit rusty. I need to practice a bit and there might be some mistakes at some point.
b) We've assumed many things for simplicity's sake. It is a simple approximation, not 100% accurate.
c) I might (and most likely will) have expressed myself poorly due to the language barrier. I'm spanish, not english. I'm also not used to using the mathematic slang and such in this language, so sorry for the confusion. ^w^;
Heh... At least I tried. ;w;
I'll give it a shot, but my calculating abilities might be a bit rusty.
Let's asume Scorge is looking at an angle of aprox. 45º (or ∏/4 rad). By extrapolating the visual data from the picture, we can see that Scorge is about 357 pixels tall (small/reduced version of the picture), which is equivalent to 9 ft, for scaling purposes. owo
To get the dimensions of the tongue, we can see that it is contained within a box of 206x186 pixels (from now on A). This makes the tongue be at a descending angle of approx. 42.07927848.
We can try to modelize this problem as a 3D affine geometry problem. We'll just need to use linear algebra to solve the problem. ^w^
Also, let's assume Scorge's tongue center is the origin, shall we? Makes it more simple to calculate by symetry (and it's probably the main focus point by now :P). We can calculate the plane that contains the projection of the line that goes across the tongue over the {X=0} plane (aka, the picture) and contains the OX axis, which we'll call p1. It's pretty simple to calculate, someone in high school should be able to do it. It's basically calculating the equations of a line in the real plane, then assume it's a projection in 3D in the {X=0} plane. The inclination is -186/206, so it's basically easy to see that the equation in R^2 is {103y+93x=0}. If we translate that to our problem, we get that p1 is basically {103z + 93y = 0}. Since we assumed Scorge was looking at an angle of 45º (and our point of view is basically aiming straight at Scorge's mouth), we will just intersect the plane we calculated before with a new vertical one that contains the further left edge of the box A and has a 45º angle towards the viewer compared to the perpendicular plane from the picture. We'll call this one p2. That one's also easy to calculate, it turns out to be p2={y=x-103}. The intersection of both results in the line: {103z+93y=0 ; y=x-103}
Let's limit the line to what we're mostly interested, shall we? The tip of the tongue and the back of it that is still visible. For simplicity's sake, we'll consider the top left corner and the bottom right corner of A as the limits. We just need to find what points do those represent in the line and calculate the distance between them. If z=93, then y=-103 and x=0. If z=-93, then y=103 and x=206.
With that, all we need to do is simply calculating the distance between the dots (0,-103,93) and (206,103,-93).
We just need to use the euclidean measure to get there. Square root of the norm of the vector that unites the dots. The result is aproximately 345.6414327 px.
With that, and knowing that Scorge in the picture is 357 px tall, which is equivalent to 9 ft, we can convert the px unit we've been using into ft. The result is 8.713649564 ft or, in other words, approx. 8 ft and 8.5 inches long.
So... There you go. Scorge's tongue is approximately 8 ft and 8.5 inches long (or at least the part seen in the picture).
Keep in mind that:
a) My calculating abilities are a bit rusty. I need to practice a bit and there might be some mistakes at some point.
b) We've assumed many things for simplicity's sake. It is a simple approximation, not 100% accurate.
c) I might (and most likely will) have expressed myself poorly due to the language barrier. I'm spanish, not english. I'm also not used to using the mathematic slang and such in this language, so sorry for the confusion. ^w^;
Heh... At least I tried. ;w;
A commendable analysis indeed. But... Its not quite finished.
The question was to find out how big the tongue was compared to you. Not just how big the tongue was. Also, if you need the width of the tongue, its just as wide as Scourge's jaw, which you can find on this picture with your method of calculating pixels.
http://www.furaffinity.net/view/14026503/
12' across. But that's from hind-leg to hind-leg so you'll have to determine the width of his face
=3
The question was to find out how big the tongue was compared to you. Not just how big the tongue was. Also, if you need the width of the tongue, its just as wide as Scourge's jaw, which you can find on this picture with your method of calculating pixels.
http://www.furaffinity.net/view/14026503/
12' across. But that's from hind-leg to hind-leg so you'll have to determine the width of his face
=3
Hmmm... Yes, I suppose you're right.
However, when we're talking about how 'big' something is, we're usually refering to volume, not just length. I would need not only the length (already calculated) and the width (rather simple to calculate by counting the pixels and converting those units to feet, which results in approx. 7 ft and 8.5 inches), but also how thick it is. With that, I might be able to calculate the tongue's volume.
Then it would be about calculating my own volume... Which might be a bit more tricky, considering a tongue is a simpler shape than a body with a head, arms, legs and a thick tail. Still, for the same reason as before, we may consider my body as a simpler form to calculate the volume of, like a cylinder or something. It's not like we're going to use much rigor in fictitional characters anyways. :P
After all that, the ratio is rather simple. Just divide the tongue's volume by mine and there we go. :3
However, when we're talking about how 'big' something is, we're usually refering to volume, not just length. I would need not only the length (already calculated) and the width (rather simple to calculate by counting the pixels and converting those units to feet, which results in approx. 7 ft and 8.5 inches), but also how thick it is. With that, I might be able to calculate the tongue's volume.
Then it would be about calculating my own volume... Which might be a bit more tricky, considering a tongue is a simpler shape than a body with a head, arms, legs and a thick tail. Still, for the same reason as before, we may consider my body as a simpler form to calculate the volume of, like a cylinder or something. It's not like we're going to use much rigor in fictitional characters anyways. :P
After all that, the ratio is rather simple. Just divide the tongue's volume by mine and there we go. :3
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